SOLUTION: A six-foot tall person walks around the earth. how much farther does the person's head travel than the person's feet?

Question 121625: A six-foot tall person walks around the earth. how much farther does the person's head travel than the person's feet?
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Remember the circumference of a circle is where d is the diameter of the circle

So let d=diameter of the earth

This means the circumference of the earth is:

Now since the person is 6 feet tall, this means we're going to add 6 to the diameter to get

So the person's head traces out the circumference:

Now subtract the second equation from the first equation to get

Distribute

Combine like terms

Simplify

So using we get

So the person's head traveled about 18.84 feet further than the person's feet.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A six-foot tall person walks around the earth. how much farther does the person's head travel than the person's feet?
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If you assume the radius of the earth is x-ft, the
circumference is 2(pi)x ft.
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If you add the 6 ft to the radius you have a radius of x+6 ft.
The circumference of the the path of the head is 2(pi)(x+6) ft.
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The difference is [2pi(x+6)]-[2(pi)x] ft
2(pi)x+12pi - 2(pi)x
= 12(pi) ft or about 37.6991 ft.
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Cheers,
Stan H.
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