SOLUTION: 1/6(5s+3)=1/2(s+11)
1/6(2c-1)=1/3c-1/6
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Question 121404This question is from textbook beginning and intermediate algebra
: 1/6(5s+3)=1/2(s+11)
1/6(2c-1)=1/3c-1/6
This question is from textbook beginning and intermediate algebra
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1/6(5s+3)=1/2(s+11)
Multiply both sides by 6 to get:
(5s+3) = 3(s+11)
5s+15 = 3s+33
2s = 18
s = 9
=================
1/6(2c-1)=(1/3)c-1/6
Multiply both sides by 6 to get:
(2c-1) = 2c - 1
0=0
The equation is true for all Real values of "c".
====================
Cheers,
Stan H.
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