# SOLUTION: Write the standard form of the line that passes through (5,-3) and has a slope perpendicular to 2x+7y=16.

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 Algebra: Linear Equations, Graphs, Slope Solvers Lessons Answers archive Quiz In Depth

 Question 120206: Write the standard form of the line that passes through (5,-3) and has a slope perpendicular to 2x+7y=16.Answer by solver91311(16897)   (Show Source): You can put this solution on YOUR website!First step is to find the required slope value. Perpendicular lines have slopes that are negative reciprocals of each other: The equation of the perpendicular is . Put this into slope-intercept form, , by solving for y. , which tells us that the slope of the perpendicular to the desired line is . Using , we now know that the slope of the desired line is . Now we have a point, (5,-3) and a slope, , so use the point slope form of the line: where m is the slope and (,) are the coordinates of the given point. Now simplify to standard form: Multiply by 2 Distribute: Add -7x to both sides Add -6 to both sides: is the desired equation, though it would be a little tidier to multiply through by -1: Hope this helps, John