SOLUTION: Hello,
I am given the image of a graph with a triangle divided into 3 parts and told to find the Area of △ DCE = __ units
and the Area of △ DBF = __ units
and the Area
Algebra.Com
Question 1199580: Hello,
I am given the image of a graph with a triangle divided into 3 parts and told to find the Area of △ DCE = __ units
and the Area of △ DBF = __ units
and the Area of △ DAG = __ units
Using the graph, calculate the area under the curve as defined by the various points on the curve.
I don't even know where to start with this equation let along solve it.
The points are:
D (0,10)
C (0,5)
E (2.5,5)
D (0,10)
B (0,2)
F (4,2)
D (0,10)
A (0,0)
G (5,0)
Thank you,
Shenette
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
From your description, I'm not sure what you/we are supposed to do with this....
Segments AB, AC, and AD are all vertical, and segments CE, BF, and AG are all horizontal, so our three triangles DCE, DBF, and DAG are all right triangles; the area of each is easily found using the formula Area = one-half base times height, where in each case the base and height are the two legs of the right triangle.
So that part should be straightforward.
But then you talk about the area under "the curve"; but there is no curve in the problem.
Points D, E, F, and G all lie on the same straight line; if segment DG is "the curve", then the area under "the curve" is the area of triangle DAG.
If in fact "the curve" is a continuous curve that passes through points D, E, F, and G, but not in a straight line, then the area under "the curve" is APPROXIMATELY the area of triangle DAG.
If this response doesn't answer the question(s) you have, re-post the problem, making it more clear exactly what the problem is.
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