SOLUTION: In 2006, the median yearly family income was about $48,200. Suppose the average annual rate of change since then is $1240 per year.
a.) Write and graph an equality for the annual
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Question 1198863: In 2006, the median yearly family income was about $48,200. Suppose the average annual rate of change since then is $1240 per year.
a.) Write and graph an equality for the annual family incomes, y, are less than the median for x years after 2006.
b.) Determine whether each of the following points is part of the solution set.
(2, 51,000)
(8, 69,200)
(5, 50,000)
(10, 61,000)
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
The equation for median family income in terms of years after 2006 is f(x)=48200+1240x
Evaluate that expression for the given x values and see whether the function value is less than or greater than the given y value. Though the wording in your post is terrible, apparently the question is to find the given points that show family incomes that are less than the median.
(2,51000): median is f(2)=50680; given is 51000. NO, the given value is NOT less than the median.
(8,69200): median is f(8)=58120; given is 69200. NO, the given value is NOT less than the median.
etc....
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