SOLUTION: Find the intercepts and sketch the graph of each line: 1. x + 2y = 2 2. 3x - y = 6 3. 4x - y = 2 4. -2x + y = 3 5. 2x + y = 1 6. 3x - 4y = -12 Given a point and the slop

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Question 1194392: Find the intercepts and sketch the graph of each line:
1. x + 2y = 2
2. 3x - y = 6
3. 4x - y = 2
4. -2x + y = 3
5. 2x + y = 1
6. 3x - 4y = -12
Given a point and the slope, graph the line and find the equation:
7. (3,1) m = 1/2
8. (-1,-1) m = -2
9. (4,-1) m = -2/3 (negative two over three)
10. (0,0) m = -4/3 (negative four over three)

Found 2 solutions by ikleyn, math_tutor2020:
Answer by ikleyn(52756)   (Show Source): You can put this solution on YOUR website!
.

Don't you want, in addition, the tutors would solve all problems from your textbook, one after other ?


And then from your next textbook, for the next year ?


And the year after next ?



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Answer by math_tutor2020(3816)   (Show Source): You can put this solution on YOUR website!

I'll show how to solve problems 1, 2, 7 and 8 as four examples to get you started.

============================================================

Problem 1

To find the x intercept, plug in y = 0 and solve for x.
x+2y = 2
x+2(0) = 2
x = 2
The x intercept is 2, meaning it crosses the horizontal x axis at 2.

Plug in x = 0 and solve for y to get the y intercept.
x+2y = 2
0+2y = 2
2y = 2
y = 2/2
y = 1
The y intercept is 1.
This is where the graph crosses the vertical y axis.

To graph this line, plot the x and y intercepts mentioned. Then draw a straight line through those two points.

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Problem 2

We follow the same idea as problem 1.

Let's find the x intercept
3x - y = 6
3x - 0 = 6
3x = 6
x = 6/3
x = 2

Now the y intercept
3x - y = 6
3(0) - y = 6
0 - y = 6
-y = 6
y = 6/(-1)
y = -6

The x and y intercepts are 2 and -6 in that order.
Meaning that this line goes through the points (2,0) and (0,-6).

Repeat these ideas for problems 3 through 6.

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Problem 7

Start with the point (3,1)
Now move 1 unit up and 2 units to the right to arrive at (5,2). This motion of "1 unit up, 2 units right" is directly from the slope 1/2.
Then draw a straight line through (3,1) and (5,2) to complete the graph.

Slope = rise/run = 1/2
rise = 1 = go 1 unit up
run = 2 = go 2 units right

Now let's find the y intercept based on this point and slope
The point (x1,y1) = (3,1) is on the line
m = 1/2 is the slope

Use the aptly named point-slope form to isolate y
y - y1 = m(x - x1)
y - 1 = (1/2)(x - 3)
y - 1 = (1/2)x + (1/2)*(-3)
y - 1 = (1/2)x - 3/2
y = (1/2)x - 3/2 + 1
y = (1/2)x - 3/2 + 2/2
y = (1/2)x + (-3+2)/2
y = (1/2)x - 1/2

The equation is in the format y = mx+b
m = 1/2 = slope
b = -1/2 = y intercept

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Problem 8

We'll use the same idea as problem 7.

Let's find the equation first.
y - y1 = m(x - x1)
y - (-1) = -2(x - (-1))
y + 1 = -2(x + 1)
y + 1 = -2x - 2
y = -2x - 2-1
y = -2x - 3

Now it is in y = mx+b form
m = -2 = slope
b = -3 = y intercept

To find another point on this line, start at the given point (-1,-1)
Then move 2 units down and 1 unit to the right to arrive at (0, -3)
This "2 unit down, 1 unit right" motion is because of the slope

slope = -2 = -2/1 = rise/run
rise = -2 = go 2 units down
run = 1 = go 1 unit right.

The graph of this equation is a straight line that goes through (-1,-1) and (0,-3)

The same ideas apply for problems 9 and 10.

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