SOLUTION: The vertices of a triangle are at A(-3, -2), B(2, 1) and C(6, 5). Find the length of the altitude
from the vertex C and the length of side AB. Then compute for the area of the tr
Algebra.Com
Question 1189504: The vertices of a triangle are at A(-3, -2), B(2, 1) and C(6, 5). Find the length of the altitude
from the vertex C and the length of side AB. Then compute for the area of the triangle.
Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
The vertices of a triangle are at
A(, )
B(, )
C(, )
the length of side AB or is equal to the distance between A and B
height to lie on a line perpendicular to AB and passes through C
use coordinates of A and B first to find a slope of the line passing through A and B
then line is
........use slope and (, )
then, a line to AB will be
.......use slope and (, )
find intersection point
...solving it, you get
convert to decimal:
,
height is distance between C and intersection point
Area:
if and , the area will be
square units
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Use the Pythagorean Formula (aka distance formula) to find the length of AB:
The length of the altitude to AB is the distance of the point (6,5) from the line containing AB.
Use the coordinates of A and B to determine that the equation of AB can be written as .
The distance of the point (p,q) from the line Ax+By+C=0 is given by the formula
Then the area of the triangle is one-half base times height:
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