SOLUTION: a party of trekkers left a staging huat at an elevation of 465 feet. and arrived at their destination at an elevation of 2347 feet/ ACcording to the map the camps were 3000 feet pa

Question 1189163: a party of trekkers left a staging huat at an elevation of 465 feet. and arrived at their destination at an elevation of 2347 feet/ ACcording to the map the camps were 3000 feet part. What was average slope between the two camps? The answer was 0.81 but i don't understand how.
Found 2 solutions by Alan3354, ankor@dixie-net.com:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
a party of trekkers left a staging huat at an elevation of 465 feet. and arrived at their destination at an elevation of 2347 feet/ ACcording to the map the camps were 3000 feet part. What was average slope between the two camps? The answer was 0.81 but i don't understand how.
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Change in elevation is the y. 2347 - 465 = 1882
Distance is the hypotenuse = r = 3000
sin(A) = y/r = 1882/3000 = ~0.6273333
A = asin(0.627333) = 38.85 degs
Slope = tan(A) = 0.80556
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Or, solve for the horizontal distance, x
x^2 = 3000^2 - 1882^2 = 5458076
x =~2336.25
----
Slope = rise/run = y/x = 1882/2336.25 = 0.80556

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a party of trekkers left a staging hut at an elevation of 465 feet.
and arrived at their destination at an elevation of 2347 feet/ ACcording to the map the camps were 3000 feet part.
What was average slope between the two camps.
:
Find the difference in elevation as they traveled 3000' between the two points
2347 - 465 = 1882 ft (rise)
Slope is the rise over run
Find the run, the horizontal dist using pythag
run =
run = 2336.25 ft
Find the slope
= .80565 ~ .81
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