SOLUTION: Equation of the line containing the given point and perpendicular to the given line (7,-6);6x+5y=4

Question 1184279: Equation of the line containing the given point and perpendicular to the given line (7,-6);6x+5y=4
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
given:
(,)

perpendicular lines have slopes negative reciprocal to each other
so, first find a slope of the given line
........solve for

=> slope
negative reciprocal is -> a slope of the perpendicular line
use point-slope formula to find equation
.........plug in and coordinates of the point (,)

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Equation of the line containing the given point and perpendicular to the given line (7,-6);6x+5y=4

As the given equation is in standard form, we switch the variables' coefficients, negate the new
y-coordinate, and then substitute the given coordinates on the right side to get the constant.
In other words, 6x + 5y = 4 becomes: 5x - 6y = 5(7) - 6(- 6)
5x - 6y = 35 + 36
5x - 6y = 71 <==== Equation of the line sought.
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