Question 1182303: The length of a rectangle is 19 m longer than the width. If the perimeter is 606 m, what are the
dimensions of the rectangle? Found 2 solutions by mananth, ikleyn:Answer by mananth(16946) (Show Source): You can put this solution on YOUR website! The length of a mrectangle is 19 m longer than the width. If the perimeter is 606 m
let width be w m
length = (w+19) m
perimeter = 2L +2w
2w +2(w+19) = 606
2w+2w+38 =606
4w+38=606
4w= 606-48
4w=558
w=139.5 m
add 19 to width to get length Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website! .
The solution by @mananth contains a FATAL ERROR, which makes the answer INCORRECT.
I came to bring a correct solution.
let width be w m
length = (w+19) m
perimeter = 2L + 2w
2w + 2(w+19) = 606
2w + 2w + 38 = 606
4w + 38 = 606
4w = 606-38
4w = 568
w = 142 m
ANSWER. The dimensions are 142 m and 142 + 19 = 161 m.