SOLUTION: find the slope-intercept equation that passes through (-1,2) and is perpendicular to the line with the equation 6y-x=12
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Question 1178882: find the slope-intercept equation that passes through (-1,2) and is perpendicular to the line with the equation 6y-x=12
Found 2 solutions by mananth, Solver92311:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
6y-x =12
6y=x+12
y= (1/6)x +12
slope = 1/2
Slope of perpendicular line will be negative reciprocal of (1/6)
slope = -6
This line with slope -6 passes through -1 ,2
plug these values to get value of b
y=mx+b
2= -6*-1 +b
2+6=b
b=-4
The required equation is y = -6x -4
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
Solve the given equation for 
in terms of 
. The coefficient on will then be the slope of the graph of that equation.
Perpendicular lines have negative reciprocal slopes. Find the negative reciprocal of the slope of the given line which will be the slope of the desired line.
Once you have the slope of the desired line, use the Point-Slope form of an equation of a line to derive the desired equation.
Point-Slope Form
)
Where )
is the given point and 
is the calculated slope.
John
My calculator said it, I believe it, that settles it
From
I > Ø
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