SOLUTION: Let f(x)=4-x^2. The equation of the tangent line to the curve at (1,3) is 2x+y=5.
a. What is the slope of the tangent line to the curve at (1,3)?
b. What is the derivat
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Question 1176982: Let f(x)=4-x^2. The equation of the tangent line to the curve at (1,3) is 2x+y=5.
a. What is the slope of the tangent line to the curve at (1,3)?
b. What is the derivative of the function when x=1?
Found 2 solutions by Solver92311, Alan3354:
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
Stop trying to game the system by posting the same question twice.
John
My calculator said it, I believe it, that settles it
From
I > Ø
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Let f(x)=4-x^2. The equation of the tangent line to the curve at (1,3) is 2x+y=5.
a. What is the slope of the tangent line to the curve at (1,3)?
---
The slope is -2, as shown in part b.
----
Or,
2x+y=5
y = -2x + 5
Slope = -2
=======================================================
b. What is the derivative of the function when x=1?
------------------
f'(x) = -2x
f'(1) = -2
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