SOLUTION: Use the given conditions to write an equation for the line in point-slope form. Passing through (1, -6) with x-intercept = -1 y - 1 = - 3x or y - 6 = - 3(x + 1) y - 6

Algebra ->  Linear-equations -> SOLUTION: Use the given conditions to write an equation for the line in point-slope form. Passing through (1, -6) with x-intercept = -1 y - 1 = - 3x or y - 6 = - 3(x + 1) y - 6      Log On


   

Question 1176814: Use the given conditions to write an equation for the line in point-slope form.
Passing through (1, -6) with x-intercept = -1

y - 1 = - 3x or y - 6 = - 3(x + 1)
y - 6 = - 3(x + 1) or y = - 3(x + 1)
y + 6 = - 3(x - 1) or y = - 3(x - 1)
y + 6 = - 3(x - 1) or y = - 3(x + 1)
Answer by MathLover1(20855) About Me  (Show Source):
You can put this solution on YOUR website!

y=mx%2Bb where m is a slope and b is y-intercept
given:
line passing through (1, -6)
with x-intercept = -1-> point (-1,0)
use points to find slope
m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
m=%280-%28-6%29%29%2F%28-1-1%29
m=6%2F%28-2%29
m=-3
so far equation is

y=+-3x%2Bb .......us a point (-1,0) to find b
0=+-3%28-1%29%2Bb
0=+3%2Bb
b=-3

and your equation is
y=+-3x-3
or
y=+-3%28x%2B1%29

equation in slope point form:
y-y%5B1%5D=m%28x-x%5B1%5D%29 .......now use a slope and point (1, -6)
y-%28-6%29=-3%28x-1%29
y%2B6=-3%28x-1%29

so, answer is: y+%2B+6=-3%28x-1%29 or y+=+-3%28x%2B1%29