SOLUTION: x²+y²+8x+8y=0

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Question 1175397: x²+y²+8x+8y=0
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
What about it?



----------------circle centered at (-4,-4) and radius .
Answer by ikleyn(52792)   (Show Source): You can put this solution on YOUR website!
.

    x² + y² + 8x + 8y = 0


    (x^2 + 8x) + (y^2 + 8y) = 


    (x*2 + 8x + 16) + (y^2 + 8y + 16) = 16 + 16


Make a square


     +  = 32


It is the standard equation of the circle centered at the point (-4,-4) with the radius of   =  units.

Solved.



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