SOLUTION: Practice Age word Problem
Alfonso went to the internet cafe traveling 6 mph and returned home traveling 10 mph. If the total trip took 8 hours, how long did Alfonso travel at e
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Alfonso went to the internet cafe traveling 6 mph and returned home traveling 10 mph. If the total trip took 8 hours, how long did Alfonso travel at e
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Question 1175281: Practice Age word Problem
Alfonso went to the internet cafe traveling 6 mph and returned home traveling 10 mph. If the total trip took 8 hours, how long did Alfonso travel at each speed? Found 4 solutions by ewatrrr, josgarithmetic, ikleyn, greenestamps:Answer by ewatrrr(24785) (Show Source):
Hi
D = rt
6mph*t = 10mph(8-t) | Distance to and from the same
16t = 80
t = 5hrs at 6mph and 3hr at 10mph
6mph*5hr = 10mph*3hr 30mi each way
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Alfonso went to the internet cafe traveling 6 mph and returned home traveling 10 mph.
If the total trip took 8 hours, how long did Alfonso travel at each speed?
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There is another way to solve.
Let d be the distance under the problem's question.
Then the time traveling to the cafe is hours.
time traveling back is hours.
Total time equation is
+ = 8 hours.
To solve it, multiply both sides by the common denominator of 30; then simplify
5d + 3d = 8*30
8d = 8*30
d = 30 miles. ANSWER
And yet a very different (and fast and easy) way to solve the problem, if a formal algebraic solution is not required.
The ratio of the speeds is 6:10 = 3:5.
Since the distances both directions are the same, the times at the two speeds are in the ratio 5:3.
8 hours total divided in the ratio 5:3 means 5 hours one direction and 3 hours the other direction.
The distance is 5 hours times 6mph = 30 miles, or 3 hours times 10 mph = 30 miles.