SOLUTION: I'm asking this question once again but I never really received an answer. Thank you. Cesar is 20 years old. Marissa is 14 years old. How many years ago was Cesar's age 3 times

Question 1175065: I'm asking this question once again but I never really received an answer. Thank you.
Cesar is 20 years old. Marissa is 14 years old. How many years ago was Cesar's age 3 times Marissa's age?

Answer by ikleyn(52788) (Show Source): You can put this solution on YOUR website!
.


Let x be "how many years ago . . . "


Then you have this equation


    20-x = 3*(14-x).


Simplify and solve


    20 - x = 42 - 3x

    3x - x = 42 - 20

      2x   = 22

       x   = 22/2 = 11.


ANSWER.  11 years ago.


CHECK.  11 years ago they were  20-11 = 9 years old (Cesar) and 14-11 = 3 years old (Marissa).


               9/3 = 3.   ! Correct !

Solved.

---------------

There is a bunch of lessons on age word problems
    - Age problems and their solutions
    - HOW TO algebreze and to solve age problems?
    - A fresh formulation of a traditional age problem
    - Really intricate age word problems
    - Selected age word problems from the archive
    - Age problems for mental solution
    - Age problem for three participants
    - Miscellaneous age problems
in this site.

Read them and become an expert in solving age problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Age word problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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