y = 2x+3 has the form  y = mx + b  (m=slope, b=y-intercept).



Parallel lines will have the equal slopes.



So we know this much: the parallel line has the form:  y = 2x + b



You can either use the point (5,-4) to solve for b, or you

can use the point-slope form of a line  y-y0 = m(x-x0) and 

plug in (5,-4) for (x0,y0).



Solving for b:

      -4 = 2(5) + b  --> b = -14  ==> eqn is y = 2x - 14



Using point-slope form:

       y - (-4) = 2(x - 5)

       y + 4 = 2x - 10

          y = 2x - 14    (same result)



 

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
 

write an equation of the line that passes through (5, -4) and is parallel to y=2x+3

y = 2x + 3, in standard form: 2x - y = - 3

Equation requested:  

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