SOLUTION: Six years ago, a woman was three times as old as her daughter. The sum of their ages was 36. Find their present ages.

Question 1173019: Six years ago, a woman was three times as old as her daughter. The sum of their ages was 36. Find their present ages.
Found 3 solutions by VFBundy, ikleyn, josgarithmetic:
Answer by VFBundy(438)   (Show Source): You can put this solution on YOUR website!
Daughter's age six years ago = d
Mother's age six years ago = 3d

d + 3d = 36

4d = 36

d = 9

Daughter's age six years ago = d = 9
Mother's age six years ago = 3d = 3(9) = 27

Daughter's age today = 9 + 6 = 15
Mother's age today = 27 + 6 = 33
Answer by ikleyn(52795)   (Show Source): You can put this solution on YOUR website!
.

After reading your post, I have a question.

It is about this passage "The sum of their ages WAS 36."

To which time moment this statement does relate ?

To the past ?     (6 years ago).

Or to the present ?     (now).

If it relates to the present, then why you use "WAS" ?

If to the past, then it should sound in other way :

"The sum of their ages WAS 36 years then".

Honestly, I do not need your clarification.

===--->>>   It is YOU, "the composer", who needs it.   <<<---===

Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
w, woman
d, daughter

Very Simple System:

ADD:

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