SOLUTION: 2[4 – 2(3 – x)] – 1 = 4[2(4x – 3) + 7] – 25 I need help solving this. I have to once again complete 4 steps and I was sent the correct answer, but once again the steps did not matc
Algebra.Com
Question 117024: 2[4 – 2(3 – x)] – 1 = 4[2(4x – 3) + 7] – 25 I need help solving this. I have to once again complete 4 steps and I was sent the correct answer, but once again the steps did not match. Any help would be great.Step 1-Simplify each side separately. step2-Isolate the variable term on one side,step 3Isolate the variable (x= a number)and step 4-Check. Substitute the proposed solution . Can someone please explain this to me ? I don't understand how to show the problem step by step like that.''.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2[4 – 2(3 – x)] – 1 = 4[2(4x – 3) + 7] – 25
Simplify the inner parentheses:
2[4 – 6+2x] – 1 = 4[8x-6 + 7] – 25
Combine like terms in the parentheses:
2[-2+2x] -1 = 4[8x+1] - 25
Simplify the parentheses again:
-4+4x-1 = 32x+4-25
Combine like terms on each side:
4x-3 = 32x-21
Subtract 4x from each side to get:
-3 = 28x-21
Add 21 to each side to get
28x = 18
Divide each side by 28 to get
x = 18/28
Reduce the fraction:
x = 9/14
================
Cheers,
Stan H.
RELATED QUESTIONS
2+3/x-5 / 4-1/x-5
2/1 + 3/x-5 / 4/1 - 1/x-5
2x-7 / 4x-21
My email was incorrect (answered by jim_thompson5910)
i need help solving these quadratic equations using the quadratic formula.
2x^2 - 5x = 3
(answered by edjones)
i need help solving these quadratic equations using the quadratic formula.
2x^2 - 5x = 3 (answered by Annabelle1)
I need help on this problem. Complete the first 4 steps for graphing the quadratic... (answered by stanbon)
7 1/9 - 4 2/3 I need help solving this I am confused
(answered by Alan3354)
I have been having trouble solving theses two problems.
(x/3)+ 2 = x / 6 {{{and}}} a+4... (answered by Fombitz)
I need help solving this problem... (answered by Fombitz)
May I have the steps for solving this problem - 1/2+(2/3÷3/4)-(4/5∙5/6?
(answered by mananth)