SOLUTION: Will someone pls. help me complete this problem There are many relationships that have a 1) Starting Point 2) Dependent and 3) Independent Variables. A linear relationship is mad

Question 1168907: Will someone pls. help me complete this problem
There are many relationships that have a 1) Starting Point 2) Dependent and 3) Independent Variables.
A linear relationship is made by a constant rate. A linear relationship MUST have a constant rate.
In tables of linear relationships, we also can identify these four components.
Below is a table showing how much money Jose has for the number of brownies he sold at a bake sale.
Find the four components of a linear relationship.
#of brownies sold Total money Jorge has
0 25
2 29
4 33
6 37
8 41

Unit Rate: $_25___
Why do we know this is a linear relationship? ___________________
Dependent Variable: __y____ = Total of money
Independent Variable: __x___ = number of brownies sold
Starting Value: _____________________________
Linear Equation: _________________________________________
Check your linear equation by using two of the values from the table above.

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
This is y=2x+25
it comes from inspection (intercept is when x=0 and y=25, and the slope is 2)
or point-slope formula y-y1=m(x-x1), m slope, (x1 y1) a point
any 2 points (0, 25) and (2, 29)--slope is 4/2=2
y-25=2(x-0)
y=2x+25
dependent and independent variables are a s you described.
Linear relationship because constant. Every 2 brownies increases money $4.
unit rate is $2, the slope of the line.
Starting point is (0, 25)

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