SOLUTION: A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the apprentice. The second apprentice worked twice as long as the first. If the carpenter and hi

Question 1168306: A carpenter had two apprentices for a job. The carpenter worked 6 hours longer than the apprentice. The second apprentice worked twice as long as the first. If the carpenter and his carpenter and his apprentices worked a total of 22 hour, how long did the carpenter work?
1st apprentice = x, 2nd apprentice = 2x, carpenter = 6x
x + 2x + 6x = 22

Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
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he carpenter worked 6 hours longer than the FIRST apprentice. The second apprentice worked twice as long as the first.
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Carpenter            6+f
First apprent.        f
Second apprent.       2f
TOTAL                 22

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