SOLUTION: write an equation of a line that passes through the point A(-6,1) and is perpendicular to the line y=3/2x+1
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Question 1168099: write an equation of a line that passes through the point A(-6,1) and is perpendicular to the line y=3/2x+1
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
perpendicular lines have slope products that are negative reciprocals.
the perpendicular line has slope of -2/3.
point slope formula y-y1=m(x-x1), (x1, y1) is point
y-1=(-2/3)(x+6)
y=(-2/3)x-3
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