SOLUTION: Find the vertex, Axis symetry for f(x)=2x^2+14X+26

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Question 1166846: Find the vertex, Axis symetry for
f(x)=2x^2+14X+26

Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.

To find a vertex, use the standard formula for its x-coordinate

    x = ,


where "a" is the coefficient at x^2 and B is the coefficient at x.


In your case,  a = 2, b = 14,  so  x =  =  = -3.5.


To find y-coordinate of the vertex, calculate the function value at x= 3.5.

Happy calculations !


---------------

On finding the maximum/minimum of a quadratic function and its vertex see the lessons
    - HOW TO complete the square to find the minimum/maximum of a quadratic function
    - Briefly on finding the minimum/maximum of a quadratic function
    - HOW TO complete the square to find the vertex of a parabola
    - Briefly on finding the vertex of a parabola


Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Finding minimum/maximum of quadratic functions".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.



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