x− 3y = −11 4x + 5y = −10 4x-12y=-44 4x+5y=-10 4x=12y-44 4x+5y=-10 The substitution: (12y-44)+5y=-10 17y-44=-10 17y=34 y=2 and you can use this to find x.
x − 3y = − 11_____x = - 11 + 3y ------ eq (i)
4x + 5y = − 10 ------ eq (ii)
4(- 11 + 3y) + 5y = - 10 -------- Substituting - 11 + 3y for x in eq (ii)
- 44 + 12y + 5y = - 10
17y = 34
Now, substitute 2 for y in eq (i) to find the value of x.