SOLUTION: The graph of a line passes through the points (0, -2) and (6, 0). What is the equation of the line?

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Question 1153791: The graph of a line passes through the points (0, -2) and (6, 0). What is the equation of the line?
Found 2 solutions by Alan3354, greenestamps:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The graph of a line passes through the points (0, -2) and (6, 0). What is the equation of the line?
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since the intercepts are given, it's
-2x + 6y = -2*6 = -12
x - 3y = 6 is the simplest.
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The long way:
find the slope m
m = diffy/diffx = 2/6 = 1/3
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y - y1 = m*(x - x1) where (x1,y1) is either point.
y - 0 = (1/3)*(x - 6)

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Also:

|x   y   1|
|0  -2   1| = 0
|6   0   1|

x*(-2*1 - 0*1) - y*(0*1 - 6*1) + 1*(0*0 - 6*-2) = 0
-2x + 6y + 12 = 0
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Several methods, several results, all equivalent.

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


(Note that the question should ask for "AN" equation of the line; there are many different forms the equation could have.)

In addition to the methods shown by the other tutor, here is another way to get the answer easily....

It's easier for me because I don't often use the two-intercept form of the equation that the other tutor showed.

Since the y-intercept (0,-2) is given, the equation is of the form



Plug in the coordinates of the other given point to determine the coefficient a:





ANSWER: AN equation of the line is


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