SOLUTION: write the equation of the line through (-p, q ) that is parallel to the line -2x+y=12 in slope intercept form and standard form

Question 114036: write the equation of the line through (-p, q ) that is parallel to the line -2x+y=12 in slope intercept form and standard form
Found 2 solutions by checkley71, josmiceli:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
2X+Y=12
Y=-2X+12 IS THE STANDARD FORM OF THIS LINE WITH A SLOPE OF -2.
THE LINE THROUGH (P,Q) WILL ALSO HAVE A SLOPE OF -2
Q=-2(-P)+b
Q=2P+b
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
(x[1], y[1]) = (p,q)
-2x + y = 12
y = 2x + 12
This is in the form
y = mx + b where m is the slope
m = 2
The general point-slope formula is
m = (y - y[1]) / (x - x[1])
2 = (y - q) / (x - p)
2x - 2p = y - q
y = 2x - 2p + q . . (slope = 2, and y-intercept = -2p + q)
2x - y - 2p + q = 0 . . (standard form)
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