SOLUTION: The sum of two numbers is 17, and twice the larger exceeds three times the smaller by 4. Find the numbers.

Question 1137117: The sum of two numbers is 17, and twice the larger exceeds three times the smaller by 4. Find the numbers.
Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
.

Let x be the smaller number.   

Then the larger number is (17-x).


What the condition says about these numbers, is this equality


    2*(17-x) = 3*x + 4.


Simplify and solve this equation


     34 - 2x = 3x + 4

     34 - 4 = 3x + 2x

     30     = 5x    ======>  x =  = 6.


ANSWER.  The smaller number is 6.  The larger number is 17-6 = 11.


CHECK.   Twice the larger is 2*11 = 22;  three times the smaller is 3*6 = 18;  22 - 18 = 4.   ! Correct !

Solved.

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