SOLUTION: Please help me find the equation of the line that is perpendicular to the line 5x+2y=15 and has an x intercept of 5.

Question 1134593: Please help me find the equation of the line that is perpendicular to the line 5x+2y=15 and has an x intercept of 5.
Found 2 solutions by MathLover1, Boreal:
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
find the equation of the line that is perpendicular to the line and has an intercept of
given:
the line
intercept of => it is a point (,)
if the line that is perpendicular to given line, and we know that perpendicular lines have slopes negative reciprocal to each other, we will find slope first
...solve for

-> given line has a slope
=>so, perpendicular line will have a slope
now use point slope formula to find equation:
.....plug in and coordinates of the point (,)

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
rewrite the line given as 2y=-5x+15
then divide by 2 for y=-(5/2)x+7.5, which is slope intercept form. The slope is -5/2.
Perpendicular lines have a negative reciprocal slope,meaning their slope product is -1. The slope of the line desired is +2/5
An x-intercept of (5, 0) is a point
point slope formula y-y1=m(x-x1) (x1, y1) point
y=(2/5)(x-5)
y=(2/5)x-2

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