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The solution by @mathsolverplus is fatally WRONG.
The solution by @MathLover1 is fatally WRONG, too.
I came to provide a correct solution.
Each line parallel to the line x - 3y = 6 has THE SAME left side
x - 3y = c, (1)
where "c" is the constant term.
To determine the constant value of "c", use the condition that the point (-6,4) belongs to the line (1).
For it, substitute the coordinates x= -6, y= 4 into equation (1) and calculate "c". You will get
-6 - 3*4 = c = -6 - 12 = -18.
Thus your final equation is
x - 3y = -18. ANSWER
Solved, completed and answered.
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- Find the slope of a straight line in a coordinate plane passing through two given points
- Equation for a straight line having a given slope and passing through a given point
- Solving problems related to the slope of a straight line
- Equation for a straight line in a coordinate plane passing through two given points
- Equation for a straight line parallel to a given line and passing through a given point
- Equation for a straight line perpendicular to a given line and passing through a given point
- OVERVIEW of lessons related to the slope of a straight line
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