hello all,
I wrote on here a couple days ago asking for help with my algebra homework with the linear equations. I understand now to do ones with the variables on the two sides of the equality like y=3x-2. I know that X=0 and also 3 and Y=2 and 0 on the T chart for the graphing.
Now the part that I'm having a hard time with is when the X and Y are on the same side of the equality like for example 2x+3=6. I'm having a rough time getting the T chart X and Ys for these problems.
any help would be really helpful as I have a quiz on Tuesday that I don't wanna fail.
Two ther examples of the ones I don't understand are 2x-3y=6 and also 3x+4y=12
thank you so much in advance.
You asked for a T-chart and nothing else. I don't know why the other person did everything except give you a T-chart.
I think you meant, 2x + 3y = 6, and NOT 2x + 3 = 6
Now, we get: 3y = - 2x + 6, and we can clearly see that the right side needs to be DIVIDED by 3, so this is why I chose values that are MULTIPLES of 3, and including 0.
These are: 0, 3, 6, 9, and 12. With that, I'm able to get integer values for y.
You now have 5 points with which to plot the graph, since you need to set up a T-table.
===============
x | y | Coordinate Point |
0 | 3y = - 2(0) + 6_____3y = 6_____y = 2 | (0, 2) |
3 | 3y = - 2(3) + 6_____3y = 0_____y = 0 | (3, 0) |
6 | 3y = - 2(6) + 6_____3y = - 6_____y = - 2 | (6, - 2) |
9 | 3y = - 2(9) + 6_____3y = - 12_____y = - 4 | (9, - 4) |
12 | 3y = - 2(12) + 6_____3y = - 18_____y = - 6 | (12, - 6) |
You should now be able to do the other 2 equations: 2x - 3y = 6 and 3x + 4y = 12, by using the same method. If not, write back!