SOLUTION: Solving a System of Equations. Solve the system, or show that it has no solution. If the system has infinitely many solutions, express them in ordered-pair form. 3/4x+1/2y=5 -1

Algebra.Com
Question 1128374: Solving a System of Equations. Solve the system, or show that it has no solution. If the system has infinitely many solutions, express them in ordered-pair form.
3/4x+1/2y=5
-1/4x-3/2y=1

Found 3 solutions by MathLover1, ikleyn, MathTherapy:
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!




Solved by pluggable solver: Solve the System of Equations by Graphing


Let's look at the first equation



Multiply both sides of the first equation by the LCD 4



Distribute



---------



Let's look at the second equation


Multiply both sides of the second equation by the LCD 4



Distribute



---------




So our new system of equations is:










In order to graph these equations, we need to solve for y for each equation.




So let's solve for y on the first equation


Start with the given equation



Subtract from both sides



Rearrange the equation



Divide both sides by



Break up the fraction



Reduce



Now lets graph (note: if you need help with graphing, check out this solver)



Graph of




So let's solve for y on the second equation


Start with the given equation



Subtract from both sides



Rearrange the equation



Divide both sides by



Break up the fraction



Reduce





Now lets add the graph of to our first plot to get:


Graph of (red) and (green)


From the graph, we can see that the two lines intersect at the point (,) (note: you might have to adjust the window to see the intersection)

Answer by ikleyn(52781)   (Show Source): You can put this solution on YOUR website!
.
Your system can be read in this way


    ((3/4)x + (1/2)y = 5,
    (-1/4)x - (3/2)y = 1,


or in this way


    3/(4x) + 1/(2y) = 5,
    -1/(4x) - 3/(2y) = 1,


depending on how to put PARENTHESES into equations.


So, the way you presented the problem is AMBIGOUS.


To avoid ambiguity, YOU must put parentheses in your formula BEFORE POSTING IT TO THE FORUM. 



Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Solving a System of Equations. Solve the system, or show that it has no solution. If the system has infinitely many solutions, express them in ordered-pair form.
3/4x+1/2y=5
-1/4x-3/2y=1
That's the most inefficient, most time-consuming, and most error-prone method I've ever seen one use to solve a system of equations, 
if I ever saw one. It is so inefficient and CONFUSING to the point where the woman who solved it got WRONG solutions. Her solutions
DO NOT SATISFY THE EQUATIONS, so IGNORE HER ENTIRE SOLUTION. Plus, why would someone even try to solve a fractional system by graphing? RIDICULOUS!
I assume the system is: ------ eq (i)
---- eq (ii)
Just multiply eq (ii) by 3 to get: ---- eq (iii)
Adding eqs (i) & (iii) results in:

- 4y = 8

Substitute - 2 for y in any of the original equations and you should get:
That's all! Nothing more, nothing less!!
RELATED QUESTIONS

graph each system of equations. then determine whether the system of equations has one... (answered by rmromero,stanbon)
Use substitution to solve each system of equations; if the system does not have exactly... (answered by Jeef Gorrdon)
Graph each system of equations using the coordinate plane provided. Then determine... (answered by jim_thompson5910)
Graph each system of equations using the coordinate plane provided. Then determine... (answered by stanbon)
Graph each system of equations using the coordinate plane provided. Then determine... (answered by elima)
Use Substitution to solve each system of equations. If the system does not have exactly... (answered by eperette)
Use Substitution to solve each system of equations. If the system does not have exactly... (answered by stanbon)
The worksheet says: Use substitution to solve each system of equations. If the system... (answered by prince_abubu)
4c= 3d + 3 c= d-1 The book says use substitution to solve each system of equations.... (answered by stanbon)