The amount of the removed contaminant in the first hours is 0.3*100 = 30 pounds; 0.7*100 = 70 pounds of the contaminant remained. The amount of the removed contaminant in the second hours is 0.3*70 = 21 pounds; 70-21 = 49 pounds of the contaminant remained. The amount of the removed contaminant in the third hours is 0.3*49 = 14.7 pounds; 49-14.7 = 34.3 pounds of the contaminant remained. Now the total removed mass of the contaminant is 100 - 34.3 = 65.7 pounds. Answer