SOLUTION: Find the area of a triangle bounded by the y-axis, the line f(x) = 6 − 6/7x, and the line perpendicular to f(x) that passes through the origin. (Round your answer to two deci

Question 1127239: Find the area of a triangle bounded by the y-axis, the line f(x) = 6 − 6/7x, and the line perpendicular to f(x) that passes through the origin. (Round your answer to two decimal places.)
*This is what I have came up with so far:
f(x)= y = 6-6/7x.
Slope =-6/7.
-1/-6/7= 7/6.
7/7x=6-6/7x
From here I am lost on what to do next. Multiplying each fraction by its reciprocal seems to be the next step, but I'm not entirely sure if it is the correct step.*

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
Find the area of a triangle bounded by:
the y-axis,
the line => a slope=
the line perpendicular to f(x) that passes through the origin
first find perpendicular line

find intersection point both lines:

find

intersection point is at (,)

graph all:

the length of the base:
the length of the altitude to the base:
the area of the triangle is:

square units

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SOLUTION: Find the area of a triangle bounded by the y-axis, the line f(x) = 6 &#8722; 6/7x, and the line perpendicular to f(x) that passes through the origin. (Round your answer to two deci

SOLUTION: Find the area of a triangle bounded by the y-axis, the line f(x) = 6 − 6/7x, and the line perpendicular to f(x) that passes through the origin. (Round your answer to two deci