SOLUTION: determine the value of k so that the line through points (0,4) and (k-2,6) has x-intercept k

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Question 1122351: determine the value of k so that the line through points (0,4) and (k-2,6) has x-intercept k
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!

,



The condition (k,0) is a point on the line
Answer by ikleyn(52782)   (Show Source): You can put this solution on YOUR website!
.

Since the post by  @josgarithmetic  contains  ERRORS,  I came to fix them. 


y = mx + b

y = ,    b= 4  is given

y=



According to the condition, the point  (k,0)  is a point on the line



 = -4


2k = -4(k-2)


2k = -4k + 8

k = -2k + 4

3k = 4


Answer.  k = .


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