SOLUTION: If Don Has 2 More Than 3 Times The Number Of Marbles Mark Has,how Many Does Each Boy Have To Sell If The Total Number Of Marbles Is 98

Question 1122301: If Don Has 2 More Than 3 Times The Number Of Marbles Mark Has,how Many Does Each Boy Have To Sell If The Total Number Of Marbles Is 98

Found 3 solutions by josgarithmetic, Boreal, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Don: 3m+2 marbles
Mark: m
Total: 98

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
D+M=98, where D=Don's marbles and M=Mark's marbles
D=3M+2
therefore, 3M+2+M=98
4M=96
M=24 ANSWER
D=74, three times M plus 2. ANSWER
Answer by ikleyn(52784)   (Show Source): You can put this solution on YOUR website!
.
Mark + Don = 98 M + (3M + 2) = 98 M + 3M + 2 = 98 4M = 98 - 2 = 96 ====> M = = 24. Answer. Mark has 24 and Don has 98 - 24 = 74.

Do not use capital letters in each word - it really annoys/irritates.

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