SOLUTION: For P=(5,2) and Q=(7,-11), Δx, Δy, and the slope of the line segment from P to Q. (use decimal value for fractional answer)
a. Δx = ___
b. Δy = ___
c. slop
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Question 1120390: For P=(5,2) and Q=(7,-11), Δx, Δy, and the slope of the line segment from P to Q. (use decimal value for fractional answer)
a. Δx = ___
b. Δy = ___
c. slope = ___
Found 3 solutions by josgarithmetic, Theo, Shin123:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
delta x means change in the value of x.
delta y means change in the value of y.
you have 2 points.
they are (5,2) and (7,-11)
slope is equal to (y2-y1) / (x2-x1)
let the point (5,2) be equal to (x1,y1)
let the point (7,-11) be equal to (x2,y2)
slope is equal to (y2-y1) / (x2-x1) = (-11 - 2) / (7 - 5) = -13/2.
-13/2 is equivalent to -6.5 in decimal form.
change in the value of x is equal to (x2 - x1) = (7 - 5) = 2
change in the value of y is equal to (y2 - y1) = (-11 - 2) = -13.
your solutions are:
change in the value of x is equal to 2
change in the value of y is equal to -13
slope is equal to -6.5
Answer by Shin123(626) (Show Source): You can put this solution on YOUR website!
Δx is the change in x and Δy is the change in y. Slope=(y2-y1)/(x2-x1) (-11-2)/(7-5) -13/2.
Δx=2
Δy=-13
Slope=-6.5
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