SOLUTION: The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 52 in., find the width of the rectangle. Solve using an algebraic equation.

Question 111773: The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 52 in., find the width of the rectangle. Solve using an algebraic equation.
Thank you.
Answer by elima(1433) (Show Source): You can put this solution on YOUR website!
The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 52 in., find the width of the rectangle. Solve using an algebraic equation.
==============================================
width = w
length = 2w+2
========================
2w+2+2w+2+w+w=52
6w+4=52
6w=48
w=8
:)
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