SOLUTION: Find the perpendicular distance of the point (2, -1) from the line y= 3x+1

Question 1116473: Find the perpendicular distance of the point (2, -1) from the line y= 3x+1
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the perpendicular distance of the point (2, -1) from the line y= 3x+1
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Find the perpendicular distance of the point (2,-1) from the line
3x - y + 1 = 0
a = 3
b = -1
c = 1
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d = (ax + by + c)/sqrt(a^2 + b^2)
d = (3*2 + 1 + 1)/sqrt(9+1) = 8/sqrt(10)
d = 0.8*sqrt(10)
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