SOLUTION: The length of a rectangle is 1 in. more than twice its width. If the perimeter of the rectangle is 50 in., find the width of the rectangle. Solve using an algebraic equation.
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Question 111333: The length of a rectangle is 1 in. more than twice its width. If the perimeter of the rectangle is 50 in., find the width of the rectangle. Solve using an algebraic equation.
Thank you very much!
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
let x=width, so 2x+1=length ___ 2(x)+2(2x+1)=50
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