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3x + 4y = 62, (1)
5x + 2y = 52. (2)
To solve the system, I will use the Elimination method. For it, multiply the equation (2) by 2 (both sides).
Keep equation (1) unchanged. You will get
3x + 4y = 62, (1')
10x + 4y = 104. (2')
Now subtract equation (1') from equation {2'). The terms "4y", that are equal in both equations
(that I made equal in both equations) will cancel each other, and you will get a single equation containing only one unknown "x"
10x - 3x = 104 - 62, or
7x = 42.
It is how the Elimination method works.
Now x = = 6.
So, you just found the value of x= 6.
Now substitute this value into either of the two given/original equations and find y. I will use equation (1):
3*6 + 4y = 62 ====> 4y = 62 - 3*6 = 44 ====> y = = 11.
Answer. x= 6, y= 11.
Check. Check the solution on your own.