SOLUTION: Find the equation of the line tangent to the circle x2 + y2 = 36 at point (11,5). Use the general equation of the line for your final answer.
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-> SOLUTION: Find the equation of the line tangent to the circle x2 + y2 = 36 at point (11,5). Use the general equation of the line for your final answer.
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Question 1106128: Find the equation of the line tangent to the circle x2 + y2 = 36 at point (11,5). Use the general equation of the line for your final answer. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The problem here is that the point (11, 5) is NOT on the circle but (sqrt (11), 5) is
x^2+y^2=36
implicit differentiation
2x+2y dy/dx=0
2y dy/dx=-2x
dy/dx=-x/y, and that is the slope of the tangent line to the circle.
calling it m, m=-sqrt(11)/5
point slope formula y-y1=m(x-x1), m slope, (x1, y1) point
y-5=(-sqrt(11)/5)(x-sqrt (11))
y-5=-(sqrt(11)/5)x+(11/5)
y=-(sqrt(11)/5)x+7.2
