SOLUTION: a boy contains rupees 1 coins and rupees 2 coins whose total value is rupees 70 if the number of rupees 1 coin is five time that of rupees 2 coins find the number of coins of each

Question 1102195: a boy contains rupees 1 coins and rupees 2 coins whose total value is rupees 70 if the number of rupees 1 coin is five time that of rupees 2 coins find the number of coins of each type
Found 2 solutions by Boreal, greenestamps:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
R2=x
R1=5x
5x(1)+x(2)=70
7x=70
x=10 R2=20R
5x=50 R1=50R
total is 70R

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Since the number of 1R coins is 5 times the number of 2R coins, imagine grouping the coins into groups of 5 1R coins and 1 2R coin.
The value of each of those groups is 5(1R)+1(2R) = 5R+2R = 7R.
If the total value of all the coins is 70R, then there must be 70/7 = 10 of those groups.
Since each group contains 5 1R coins and 1 2R coin, the number of 1R coins is 10*5 = 50 and the number of 2R coins is 10+1 = 10.
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