SOLUTION: Find the line which goes through the point (2,-5) and is perpendicular to the line 3y-7x=2. (write the numerical coefficient of each term to complete the required equation

Question 1099788: Find the line which goes through the point (2,-5) and is perpendicular to the line 3y-7x=2. (write the numerical coefficient of each term to complete the required equation
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
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...perpendicular to the line 3y-7x=2, ...
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... goes through the point (2,-5),...
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Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
Find the line which goes through the point (2,-5) and is perpendicular to the line 3y-7x=2.
(write the numerical coefficient of each term to complete the required equation
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The given line 3y - 7x = 2 is y = and has the slope . Hence, the perpendicular line has the slope , which is reciprocal with the opposite sign. The the equation of this perpendicular line passing through the point (2,-5) is y - (-5) = . Multiply both sides by 7. You will get 7y + 35 = -3(x-2), or 7y + 35 = -3x + 6, or finally 3x + 7y = -29.

The line 3y - 7x = 2 (original line, red) and the line 3x + 7y = -29 (perpendicular passing through (2,-5), green)

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The solution by @josgarithmetic is W R O N G. Simply ignore it.

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