FYI:
IGNORE all such answers!
3x + 2y = 48, (1) 6x + 6y = 64. (2) Divide eq(2) by 2 (both sides). You will get the modified system 3x + 2y = 48, (1') 3x + 3y = 32. (2') Subtract eq(1) from eq(2) (both sides). You will get y = 32 - 48 = -16. Thus you just found the solution for y. Now substitute it into either equation (1) or (2). I will substitute into eq(1). You will get 3x + 2*(-16) = 48 ====> 3x = 48 + 32 = 80 ====> x =. Answer. The solution is (x,y) = ( ,-16).