Question 1097467: Write the equation of the line that is perpendicular to y=-10/11x+53/11 and passes through (-10,-10) Found 3 solutions by Alan3354, josgarithmetic, MathTherapy:Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website! Write the equation of the line that is perpendicular to y=-10/11x+53/11 and passes through (-10,-10)
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Step 1, find the slope of the given line. Call it m1.
Step 2, the slope of lines perpendicular is the negative inverse of m1, = -1/m1. Call it m2.
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Step 3, use y-y1 = m2*(x-x1) where (x1,y1) is the point.
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The practice will do you good.
I don't need any. Answer by josgarithmetic(39629) (Show Source): You can put this solution on YOUR website! Answer by MathTherapy(10556) (Show Source): You can put this solution on YOUR website!
Write the equation of the line that is perpendicular to y=-10/11x+53/11 and passes through (-10,-10)
Slope of given line:
Slope of perpendicular line:
Equation requested:
IGNORE all other RUBBISH!