.
Let a and b be the digits of your number n, so that n = 10a + b.
The number after reversing digits is 10b + a.
Then from the condition you have the system of two equations for the unknowns a and b:
.
Now, simplify it:
.
Simplify it one more time:
.
So, you have, actually, only ONE equation for the digits and do not have any additional info.
Therefore, the answer is not unique.
All the numbers 18, 27, 36, 45, 54, 63, 72, 81 are the solutions.
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On problems for digits reversing see the lesson
- Word problems on reversing digits of numbers
in this site.
the sum of two digit number and the number obtained by interchanging its digits is 99. find the number
Let the tens and units digits be T and U, respectively
Then the number is 10T + U, and the reversed number is 10U + T
We then get: 10T + U + 10U + T = 99
11T + 11U = 99
11(T + U) = 11(9)
T + U = 9
Therefore, any 2 digits that sum to 9 will satisfy. It's NOT unique as there're more than 1 answers.
In other words, the digits can be: 1 and 8, or the number 18, the reverse being 81
2 and 7, or the number 27, the reverse being 72
3 and 6, or the number 36, the reverse being 63
4 and 5, or the number 45, the reverse being 54