2y = 4x + 2 (1) Y + 3 = 2x (2) Divide the first equation by 2 (both sides) and write both equations in the standard form. 2x - y = -1, 2x - y = 3. You see that the left sides of these equations are identical, while right sides are different. Therefore, the original system of two equations has no solutions. Answer. The system has no solutions.