SOLUTION: Dear Tutors can you please assist me with this problem thank you A line with a slope of -10 passes through the points (8,-5) and (h,5). What is the value of h?

Question 1088532: Dear Tutors can you please assist me with this problem thank you
A line with a slope of -10 passes through the points (8,-5) and (h,5). What is the value of h?
h=

Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
slope is equal to (y2 - y1) / (x2 - x1)

(x1,y1) is a point on the line.

(x2,y2) is another point on the line.

assign (8,-5) to (x1,y1)

assign (h,5) to (x2,y2)

slope formula becomes (5 - (-5)) / (h - 8)

simplify to get slope = 10 / (h-8)

since slope = -10, the equation becomes -10 = 10 / (h-8)

multiply both sides of the equation by (h-8) to get -10 * (h - 8) = 10

simplify to get -10h + 80 = 10

subtract 80 from both sides of the equation to get -10h = -70

divide both sides of the equation by -10 to get h = 7

the two points are:

(x1,y1) = (8,-5)

(x2,y2) = (7,5)

(y2-y1) / (x2-x1) = 10/-1 = -10

solution looks good.

h = 7

RELATED QUESTIONS
Hi Tutors can you please assist me with the problem below. Thank you A line has a... (answered by josgarithmetic)

HI! Can you please assist me with this problem. Thank you A line has a slope of... (answered by jim_thompson5910)

Dear tutors help : The points (2,v) and (1,-6) fall on a line with a slope of 10. (answered by MathLover1,MathTherapy)

Dear Tutors can you please help me solve the problem below. Thank you A line has a... (answered by math_helper)

Find an equation of the line passing through the points (-1,3)and (-2,-5) can you... (answered by Boreal)

Dear Tutor can you please assist me with this problem on Multiply Polynomials (answered by Fombitz)

Can you please assist me with this math problem thank you Find the... (answered by rothauserc)

Can you please help me with this problem: What is the equation (in slope-intercept... (answered by checkley71)

Can someone please help me with this problem. Find the slope of the line passing through (answered by stanbon)