SOLUTION: How do I find equations for lines parallel or perpendicular to y = ⅔ x + 2; (6, -3)
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Question 1085966: How do I find equations for lines parallel or perpendicular to y = ⅔ x + 2; (6, -3)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
parallel has same slope
use point slope formula y-y1=m(x-x1), m slope, (x1,y1) point
y+3=(2/3)(x-6), watch the sign
y=(2/3(x)-7
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perpendicular lines have the negative reciprocal slope, so negative reciprocal os 2/3 is -3/2
y+3=(-3/2)(x-6)
y+3=-(3/2)x+9
y=(-3/2)x-12
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The line going through (0,2) is the line given.
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