SOLUTION: solve the following simultenous equations by inverse and matrix method {3a+3b+c=21} {5a+10b+2c=52) {8a+32b+4c=136} Thank you. Jane

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Question 1079389: solve the following simultenous equations by inverse and matrix method
{3a+3b+c=21}
{5a+10b+2c=52)
{8a+32b+4c=136}
Thank you.
Jane

Answer by Edwin McCravy(20066)   (Show Source): You can put this solution on YOUR website!
Question 485960
We convert the system of equations:



to the matrix equation:




I will assume that you know how to find the inverse of the 
coefficient matrix.  If not let me know in the thank-you
note form below and I'll get back to you by email. It is

 

Now we left multiply both sides of the matrix equation by
the inverse of the coefficient matrix:



I will also assume that you know how to multiply
matrices.  If you don't, let me know below.
Multiplying the matrices on the right and
multiplying the first two on the left, we get:



That's the identity matrix on the left, which is what you
always get when you multiply a matrix by its inverse.
Multiplying the identity matrix by the column matrix of 
variables on the left we get



So a = 2, b = 3, c = 6.

Even though I did the entire problem, working with the
entire matrix equation, you can see that you can use a 
shortcut of just doing the right side only, which is to 
multiply the inverse of the coefficient matrix by the
column matrix of constants.  That's because in every 
case the left side will be the same as above.  

Edwin

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